Frequent question: How do you calculate the energy needed to boil water?

How do you calculate the amount of energy needed to boil?

The energy needed E=SH times change in temperature times the total mass in grams(Which is 1000gram for a liter of water). That gives you 4.184•79•1000 which is 330,536J, or 330.54KJ.

How much energy does it take to boil a cup of water?

4.184 * 250 * 79 = 82,634 joules. In other words, it takes more than 82.6 kJ to heat a cup of water to boiling point!! We usually only need between 1 and 10 joules to heat blood/hair sufficiently to destroy their proteins.

How much energy is required to boil 150g water?

= 150 g x 4.184 J/g/K x (373 – 298) K = 47,070 J. Thus, 47,070 J are needed to increase the temperature of 150 g of water from 25 degrees C to its boiling point of 100 degrees C.

What is the most economical way to boil water?

For appliances – microwave, electric tea kettle, electric stovetop – the most efficient appliance is the one that can boil water while pulling in the least amount of electricity via its plug.

How many watt hours does it take to boil water?

In electric kettles the water is in direct contact with the heating element, there is no pot to heat and most kettles include an integrated lid. The electric kettle averaged around 1200 watts and took 125 seconds to boil the water, which translates to 0.04 kilowatt-hours (kWh) of electricity consumed.

Is Food potential energy?

The chemical energy stored in food is a type of potential energy. Therefore, it can be transformed into kinetic energy.

How much energy does it take to boil a gram of water?

For water at its normal boiling point of 100 ºC, the heat of vaporization is 2260 J g-1. This means that to convert 1 g of water at 100 ºC to 1 g of steam at 100 ºC, 2260 J of heat must be absorbed by the water.

How much energy does it take to boil a 125 g sample of water?

The change in temperature is (100°C – 27°C) = 73°C. Since the specific heat of water is 4.18J/g/°C we can calculate the amount of energy needed by the expression below. Energy required = 4.18 J/g/°C X 100g X 73°C = 30.514KJ.